- 时间:2020-02-25 20:24 编辑: 来源: 阅读:
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摘要:Ruby中用线程实现经典的生产者消费者问题代码实例
[b]示例代码:[/b]
require "thread"
puts "ProAndCon"
queue = Queue.new #用队列Queue实现线程同步
producer = Thread.new do
10.times do |i|
sleep rand(i) # 让线程睡眠一段时间
queue << i
puts "#{i} produced"
end
end
consumer = Thread.new do
10.times do |i|
value = queue.pop
sleep rand(i/2)
puts "consumed #{value}"
end
end
consumer.join #等待consumer线程的输出完成再关闭此进程
[b]运行结果:[/b]
ProAndCon
produced
produced
consumed 0
produced
produced
consumed 1
consumed 2
consumed 3
produced
consumed 4
produced
consumed 5
[b]美化的代码图:[/b]
[img]http://files.jb51.net/file_images/article/201501/2015122112707052.png?2015022112717[/img]