我有以下几行： d:\Projects\qqq\Development\qqq.MySol1.sln d:\Projects\qqq\qqqDevelopment\qqqMySol2.sln d:\Projects\qqq\Development\MyInstaller.sln d:\Projects\qqq\qqq\Development\MyInstaller.sln d:\Projects\Development\MyInstaller.sln 我需要一个正则表达式，这将导致捕获： Line 1: Development and MySol1.sln Line 2: Development and MySol2.sln Line 3: Development and MyInstaller.sln Line 4: Development and MyInstaller.sln Line 5: Development and MyInstaller.sln 因此，一个正则表达式，将删除（忽略）字qqq从行。 我一直在试图与调节，并有部分的解决方案： 这导致： Line 1: Development and .MySol1.sln Line 2: qqqDevelopment and MySol2.sln Line 3: Development and nstaller.sln Line 4: Development and nstaller.sln Line 5: Development and nstaller.sln 因此，.{3}应固定 1.我认为，应该工作： .*\\(?:qqq)?(?<A>.*)\\(?:qqq)?(?<B>.*)