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js检查页面上有无重复id的实现代码

  • 时间:2021-05-21 01:02 编辑: 来源: 阅读:
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摘要:js检查页面上有无重复id的实现代码
方法一:
[u]复制代码[/u] 代码如下:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD>   <TITLE> New Document </TITLE>   <script type="text/javascript">     window.onload = function(){         var tags = document.getElementsByTagName("*"),             count = tags.length, time, ret = {}, id;         time = new Date();         for(var i = 0; i < count; i++){             id = tags[i].id;             if(id){                 if(ret[id]){                     alert(id + "/n用时:" + (new Date() - time));                     return;                 }else{                     ret[id] = true;                 }             }         }         alert("未找到相同ID");     }   </script> </HEAD> <BODY>   <script type="text/javascript">     (function(){         var html = [], rnd = parseInt(Math.random() * 1000);         for(var i = 0; i < 1000; i++){             html.push("<div id='a" + i + "'>" + i + "</div>");         };         //在随机位置插入一个随机的id         i = parseInt(Math.random() * 1000);         html[i] = html[i] + ("<div id='a" + rnd + "'>" + rnd + "</div>");         document.write(html.join(""));     })();   </script> </BODY> </HTML>
方法二:
[u]复制代码[/u] 代码如下:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD>   <TITLE> New Document </TITLE>   <script type="text/javascript">     function createDiv(){         var html = [], id;         for(var i = 0; i < 2000; i++){             id = "divId" + parseInt(Math.random() * 10000);             html.push("<div id='" + id + "'>" + id + "</div>");         }         document.body.innerHTML = html.join("");     }     window.onload = function(){         createDiv();         var oID = {} , result = {}, arr = [],             tags = document.getElementsByTagName("*");         for(var i = 0, id; i < tags.length; i++){             id = tags[i].id;             if(id){                 oID[id] = oID[id] ? oID[id] + 1 : 1;                 if(oID[id] > 1){                     result[id] = id + " " + oID[id]; } } } for(var o in result){             arr.push(result[o]);         }         alert(arr.join("/t"));     };   </script> </HEAD> <BODY> </BODY> </HTML>
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