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android之HttpPost&HttpGet使用方法介绍

  • 时间:2021-09-23 00:36 编辑: 来源: 阅读:
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摘要:android之HttpPost&HttpGet使用方法介绍
直接讲用法,先知道怎么用,再知道怎么回事 [b]1、HttpPost[/b]
[u]复制代码[/u] 代码如下:
try{ //创建连接 HttpClient httpClient = new DefaultHttpClient(); HttpPost post = new HttpPost(url); //设置参数,仿html表单提交 List<NameValuePair> paramList = new ArrayList<NameValuePair>(); BasicNameValuePair param = new BasicNameValuePair("param1",paramValue); paramList.add(param); post.setEntity(new UrlEnodedFormEntity(paramList,HTTP.UTF-8)); //发送HttpPost请求,并返回HttpResponse对象 HttpResponse httpResponse = httpClient.execute(post); // 判断请求响应状态码,状态码为200表示服务端成功响应了客户端的请求 if(httpResponse.getStatusLine().getStatusCode() == 200){ //获取返回结果 String result = EntityUtils.toString(httpResponse.getEntity()); } }catch(Exception e){}
[b]2、HttpGet[/b]
[u]复制代码[/u] 代码如下:
try{ HttpClient httpClient = new DefaultHttpClient(); //仿地址链接直接跟参数,如:http://127.0.0.1:8080/test/test.php?name=; HttpGet httpGet = new HttpGet(url); HttpResponse httpResponse = httpClient.execute(httpGet); if(httpResponse.getStatusLine().getStatusCode()==200){ String result = EntityUtils.toString(httpResponse.getEntity()); } }catch(Exception e){}
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