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js获取电脑分辨率的思路及操作

  • 时间:2021-03-18 05:43 编辑: 来源: 阅读:
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摘要:js获取电脑分辨率的思路及操作
在做页面时,用户要求,不同的分辨率,弹出窗口的位置不同,我想是不是先获得屏幕宽度,然后付值给变量,再在onclick中设置参数
[u]复制代码[/u] 代码如下:
<script> alert(screen.width+"*"+screen.height) </script>
[u]复制代码[/u] 代码如下:
<script> function centerWindow(url,w,h){ l=(screen.width-w)/2 t=(screen.height-h)/2 window.open(url,'','left='+l+',top='+t+',width='+w+',height='+h) } </script> <input type=button onclick="centerWindow('about:blank',200,200)"> --------------------------------------------------------------- <body> <SCRIPT LANGUAGE="JavaScript"> var s ="网页可见区域宽:"+ document.body.clientWidth; s+="\r\n网页可见区域高:"+ document.body.clientHeight; s += "\r\n网页正文全文宽:"+ document.body.scrollWidth; s += "\r\n网页正文全文高:"+ document.body.scrollHeight; s += "\r\n网页正文部分上:"+ window.screenTop; s += "\r\n网页正文部分左:"+ window.screenLeft; s += "\r\n屏幕分辨率的高:"+ window.screen.height; s += "\r\n屏幕分辨率的宽:"+ window.screen.width; s +="\r\n屏幕可用工作区高度:"+ window.screen.availHeight; s +="\r\n屏幕可用工作区宽度:"+ window.screen.availWidth; alert(s); </SCRIPT> --------------------------------------------------------------- <SCRIPT LANGUAGE="JavaScript"> <!-- Begin function redirectPage() { /*var url640x480 = "http://www.yourweb.com/640x480.html";**记得改相应的页面*/ var url800x600 = "index1.asp"; var url1024x768 = "index2.asp"; /*if ((screen.width == 640) && (screen.height == 480)) window.location.href= url640x480;*/ if (screen.width <= 800 ) window.location.href= url800x600; else if ((screen.width >= 1024) ) window.location.href= url1024x768; } // End --> </script>
这段代码是根据不同的屏幕显示不同的页面 下面是传递这个参数的
[u]复制代码[/u] 代码如下:
<script language=JavaScript> document.write("<a href='WebStat/index.asp'>"); document.write("<img src='WebStat/count.asp?Referer=<%=refer%> &Width="+escape(screen.width)+"&Height="+escape(screen.height)+ "' border=0 width=1 height=1>"); document.write("</a>"); </script>
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