源码网商城,靠谱的源码在线交易网站 我的订单 购物车 帮助

源码网商城

C实现分子沉积模拟的示例代码

  • 时间:2022-06-23 22:16 编辑: 来源: 阅读:
  • 扫一扫,手机访问
摘要:C实现分子沉积模拟的示例代码
[u]复制代码[/u] 代码如下:
/******************分子沉积模拟器****************/ /* 主要功能:模拟单片分子沉积                    */ /*-------------------By TJX---------------------*/ #include<stdio.h> #include<graphics.h> #include<alloc.h> #include<stdlib.h> #include<time.h> float dir;    /*移动方向概率参数在0-1间*/ int main() {int i,count=0;                /*设置分子总数*/ int gdriver=DETECT, gmode,errorcode,size; int x,y; time_t lt; unsigned seed; char **a; void *buf,*buf1; a=(char**)malloc(100*sizeof(char*));     /*分配内存空间*/ for(i=0;i<100;i++)     {a[i]=(char*)malloc(167*sizeof(char));      memset(a[i],0,167);}         /*用0初始化数组,0代表该处无分子,1代表有分子*/ lt=time(NULL); seed=(unsigned)lt; srand(seed);                    /*用时间初始化随机器*/ printf("\n\n\n\n\tPlease Input The Pf(0<=pf<=1):\n"); do{      scanf("%f",&dir);                  /*获取移动方向概率参数*/      getch();     }while(dir<0||dir>1); clrscr(); initgraph(&gdriver, &gmode, "c:\\tc");     /*初始化图形驱动*/      errorcode = graphresult();              /*检测是否初始化成功*/     if (errorcode != grOk) /* an error occurred 错误发生则退出*/     {        printf("Graphics error: %s\n", grapherrormsg(errorcode));        printf("Press any key to halt:");        getch();        for(i=0;i<100;i++) free(a[i]);        free(a);        exit(1); /* terminate with an error code */     }     setbkcolor(BLUE);                 cleardevice();     size=imagesize(2,2,4,4);               /*返回用于橡皮擦的图片字节数*/     buf=malloc(size);               /*为其分配内存*/     size=imagesize(9,49,11,51);         /*返回用于覆盖的图片字节数*/     buf1=malloc(size);                   drawscreen(buf,buf1);     drawtxtscr(dir);               /*绘制界面*/     putimage(9,49,buf,COPY_PUT);         /*清除9,49处的分子*/     getch();     do{        x=3*(int)(166.0*(rand()/32767.0));    /*随机生成分子出现位置*/             move(x,a,buf,buf1);              /*分子移动*/        }while(++count<10);     getch();     closegraph();     free(buf);     free(buf1);                    /*释放内存*/                             for(i=0;i<100;i++) free(a[i]);     free(a);     return 0; } drawtxtscr() { int ud[8]={10,320,490,320,490,400,10,400};     char s[60];     setcolor(YELLOW);     setlinestyle(0,0,NORM_WIDTH);     setfillstyle(1,CYAN);     fillpoly(4,ud);     sprintf(s,"The downwards probobility of the atom equal:\n%.1f",dir);     settextstyle(2,0,4);     outtextxy(30,335,s);     settextstyle(4,0,2);     outtextxy(190,375,"---TJX---");     } drawscreen(void *bu,void *bu1)               /*绘制工作区*/ { int userdata[8]={0,0,501,0,501,300,0,300};     int size;     setbkcolor(BLUE);     cleardevice();     setcolor(GREEN);     setlinestyle(0,0,NORM_WIDTH);      /*设置线形*/     setviewport(69,69,639,479,1);     /*设置显示区*/     setfillstyle(1,GREEN);              fillpoly(4,userdata);     getimage(2,2,4,4,bu);                /*将获取模拟橡皮擦存入内存*/     setcolor(YELLOW);     setfillstyle(1,YELLOW);     circle(10,50,1);               /*绘制模拟分子*/     floodfill(10,50,YELLOW);          /*填充黄色*/     getimage(9,49,11,51,bu1);          /*将模拟分子存入内存*/ } move(int x,char **a,void *buf,void *buf1) { float dirction; int sx,sy=0,i,j,end=0,start=0; sx=x; do{       if(sx==0) start=1;               /*判定分子出现位置*/       else if(sx>0&&sx<498) start=2;       else start=3;       j=sx/3;                    /*记录*/       i=sy/3;       if(start==1&&sy<297&&(a[i+1][j]+a[i][j+1])==0) /*判定其四周是否有分子存在*/         { dirction=(float)(rand()/32627.0);      /*随机生成分子运动方向*/           if(dirction<=dir) {sy=sy+3 ;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx,sy-3,buf,COPY_PUT);}           else if(dirction>dir&&dirction<=(1+dir)/2)                             {sy=sy+3;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx,sy-3,buf,COPY_PUT);}           else if(dirction>(1+dir)/2 && dirction<=1.0)                              { sx=sx+3;                                             putimage(sx,sy,buf1,COPY_PUT);                                putimage(sx-3,sy,buf,COPY_PUT); }           }                                else if(start==2&&sy<297&&(a[i][j-1]+a[i+1][j]+a[i][j+1])==0)            { dirction=(float)(rand()/32627.0);            if(dirction<=dir) {sy=sy+3;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx,sy-3,buf,COPY_PUT);}           else if(dirction>dir&&dirction<=(1+dir)/2)                             {sx=sx-3;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx+3,sy,buf,COPY_PUT);}           else if(dirction>(1+dir)/2 && dirction<=1.0)                              { sx=sx+3;                                             putimage(sx,sy,buf1,COPY_PUT);                                putimage(sx-3,sy,buf,COPY_PUT); }             }        else if(start==3&&sy<297&&(a[i][j-1]+a[i+1][j])==0)            { dirction=(float)(rand()/32627.0);             if(dirction<=dir) {sy=sy+3 ;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx,sy-3,buf,COPY_PUT);}             else if(dirction>dir&&dirction<=(1+dir)/2)                             {sx=sx-3;                              putimage(sx,sy,buf1,COPY_PUT);                              putimage(sx+3,sy,buf,COPY_PUT);}             else                              { sy=sy+3;                                             putimage(sx,sy,buf1,COPY_PUT);                                putimage(sx,sy-3,buf,COPY_PUT); }              }          else end=1;       }while(!end);      a[i][j]=1; }
  • 全部评论(0)
联系客服
客服电话:
400-000-3129
微信版

扫一扫进微信版
返回顶部