re.sub(pattern, repl, string[, count])
re.subn(pattern, repl, string[, count])
#coding=utf-8 import re str = "https://i.cnb1logs.co2m/Edi3tPosts.asp4x?opt=999" pattern=re.compile(r'(\.)') print '\. :' ,re.sub(pattern,'-',str) pattern=re.compile(r'\/([^*]+)\/') print '\/([^*]+)\/ :' ,re.sub(pattern,r'<em>\1<em>',str) pattern = re.compile(r'(\w+)(\w+)(\d+)') #先切片测试 print re.split(pattern,str) print re.sub(pattern,r'\3 \1',str) #subn统计sub替换次数 print re.subn(pattern,r'\3 \1',str)
\. : https://i-cnb1logs-co2m/Edi3tPosts-asp4x?opt=999
\/([^*]+)\/ : https:<em>/i.cnb1logs.co2m<em>Edi3tPosts.asp4x?opt=999
['https://i.', 'cn', 'b', '1', 'logs.', 'c', 'o', '2', 'm/', 'Ed', 'i', '3', 'tPosts.', 'as', 'p', '4', 'x?opt=', '9', '9', '9', '']
https://i.1 cnlogs.2 cm/3 EdtPosts.4 asx?opt=9 9
('https://i.1 cnlogs.2 cm/3 EdtPosts.4 asx?opt=9 9', 5)
***Repl Closed***
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