源码网商城,靠谱的源码在线交易网站 我的订单 购物车 帮助

源码网商城

ajax php传递和接收变量实现思路及代码

  • 时间:2020-05-26 03:07 编辑: 来源: 阅读:
  • 扫一扫,手机访问
摘要:ajax php传递和接收变量实现思路及代码
So, your jQuery might be something like.....
[u]复制代码[/u] 代码如下:
$.ajax({ url: 'query.php', data: {id:10}, datatype: json success: function(results) { if (results.msg == 'success') { for (var i in data) { $('#content').append( 'id = ' + results.data[i].id + ', description = ' + results.data[i].description + ', msrp = ' + results.data[i].msrp ); } } else { $('#content').append(results.msg); } } });
And your php....
[u]复制代码[/u] 代码如下:
if (isset($_GET['id'])) { $sql = "SELECT id, description, msrp FROM tbl WHERE id = '{$_GET['id']}'"; $return = array(); if ($result = mysql_query($sql)) { if (mysql_num_rows($result)) { $return['msg'] = 'success'; while ($row = mysql_fetch_assoc($result)) { $return['data'][] = $row; } } else { $return['msg'] = 'No results found'; } else { $return['msg'] = 'Query failed'; } header("Content-type: application/json"); echo json_encode($result); }
  • 全部评论(0)
联系客服
客服电话:
400-000-3129
微信版

扫一扫进微信版
返回顶部