该方式直接保存为HTML文件，也可以是文本文件，其它格式效果不是很好
accept@qq.com");//接收邮箱
byte[] bytes = System.Text.Encoding.Default.GetBytes
(@"<table><tr><td width=150>1234567891234567
</td><td width=80>12345678</td></tr></table>");
MemoryStream ms = new MemoryStream(bytes);
ContentType ct = new ContentType();
//附件文件类型
ct.MediaType = MediaTypeNames.Text.Html;
//附件名称，可以是其它后缀名
ct.Name = "附件名称" + DateTime.Now.ToString() + ".html";
mmsg.Attachments.Add(new Attachment(ms, ct));
//SMTP简单邮件协议
System.Net.Mail.SmtpClient sc
= new System.Net.Mail.SmtpClient();
sc.Host = "127.0.0.1";//主机地址
sc.Port = 25;//端口
//发送邮箱账号和密码
sc.Credentials =
new System.Net.NetworkCredential("account", "password");
//发送邮箱
mmsg.From = new MailAddress("account@qq.com");
sc.Send(mmsg);
//释放流资源
ms.Close();
ms.Dispose();
另附上一个.net使用smtp发送带附件邮件的实例
**********@gmail.com"/>//Email Address
<add key="EmailPassword" value="*********"/> //Emial PWD
<add key="SmtpServer" value="smtp.gmail.com"/>
<add key="SmtpPort" value="587"/>
<--带附件版本->
var fromAddress = "allenyinj@gmail.com";
string fromPassword = "yj1989120";
const string subject = "CV";
var smtp = new SmtpClient
{
Host = "smtp.gmail.com",
Port = 587,
EnableSsl = true,
DeliveryMethod = SmtpDeliveryMethod.Network,
UseDefaultCredentials = false,
Credentials = new NetworkCredential(fromAddress, fromPassword)
};
MailMessage email=new MailMessage(fromAddress, "allen.yin.jun@gmail.com");
email.Subject = "INLINE attachment TEST";
email.IsBodyHtml = true;
string attachmentPath = "C:\\3.jpeg";
Attachment inline = new Attachment(attachmentPath);
inline.ContentDisposition.Inline = true;
inline.ContentDisposition.DispositionType = DispositionTypeNames.Inline;
//inline.ContentId = "1";
//inline.ContentType.MediaType = "image/png";
inline.ContentType.Name = Path.GetFileName(attachmentPath);
email.Attachments.Add(inline);
email.Body = "test";
smtp.Send(email);
email.Dispose();
//如果没有路径，用Stream
Attachment letter = new Attachment(FileUploadLetter.FileContent, FileUploadLetter.PostedFile.ContentType);
letter.ContentDisposition.Inline = true;
letter.ContentDisposition.DispositionType = DispositionTypeNames.Inline;
//inline.ContentId = "1";
letter.ContentType.MediaType = FileUploadLetter.PostedFile.ContentType;
letter.ContentType.Name = Path.GetFileName(FileUploadLetter.PostedFile.FileName);
letter.Name = Path.GetFileName(FileUploadLetter.PostedFile.FileName);
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