先看看删除之前的表结构： mysql> select * from test; +------+--------+----------------------------------+------------+------------+------------+------------+ | t_id | t_name | t_password                       | t_birth    | birth      | birth1     | birth2     | +------+--------+----------------------------------+------------+------------+------------+------------+ |    1 | name1  | 12345678901234567890123456789012 | NULL       | 1990-01-01 | 0000-00-00 | 2013-01-01 | |    2 | name2  | 12345678901234567890123456789012 | 2013-01-01 | NULL       | 0000-00-00 | 2013-01-01 | +------+--------+----------------------------------+------------+------------+------------+------------+ 2 rows in set (0.00 sec) 执行删除命令，使用drop关键字。 基本的语法为：alter table <表名> drop column <字段名>; 具体的命令如下： mysql> alter table test drop column birth1; Query OK, 0 rows affected (0.13 sec) Records: 0  Duplicates: 0  Warnings: 0 看看删除后的结果，是不是已经没有birth1字段了？ mysql> select * from test; +------+--------+----------------------------------+------------+------------+------------+ | t_id | t_name | t_password                       | t_birth    | birth      | birth2     | +------+--------+----------------------------------+------------+------------+------------+ |    1 | name1  | 12345678901234567890123456789012 | NULL       | 1990-01-01 | 2013-01-01 | |    2 | name2  | 12345678901234567890123456789012 | 2013-01-01 | NULL       | 2013-01-01 | +------+--------+----------------------------------+------------+------------+------------+ 2 rows in set (0.00 sec) 关于MySQL中根据生日计算年龄的SQL语句日期函数，本文就介绍这么多，希望对大家有所帮助，谢谢！