- 时间:2020-06-12 03:37 编辑: 来源: 阅读:
- 扫一扫,手机访问
摘要:用PHP获取Google AJAX Search API 数据的代码
[url=http://code.google.com/apis/ajaxsearch/documentation/#fonje]http://code.google.com/apis/ajaxsearch/documentation/#fonje[/url]
[url=http://code.google.com/apis/ajaxsearch/signup.html]http://code.google.com/apis/ajaxsearch/signup.html[/url]
由此,我们可以写个函数像这样
function google_search_api($args, $referer = 'http://www.1sucai.cn/', $endpoint = 'web'){
$url = "http://ajax.googleapis.com/ajax/services/search/".$endpoint;
if ( !array_key_exists('v', $args) )
$args['v'] = '1.0';
$url .= '?'.http_build_query($args, '', '&');
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_REFERER, $referer);
$body = curl_exec($ch);
curl_close($ch);
return json_decode($body);
}
// 使用示例
$rez = google_search_api(array(
'q' => '21andy.com', // 查询内容
'key' => '你申请到的API KEY',
'userip' => '你的IP地址',
));
header('Content-type: text/html; charset=utf-8;');
echo '<xmp>';
print_r($rez);
echo '</xmp>';