#include <math.h>
double log (double x);
x = eret
#include <stdio.h>
#include <math.h>
int main ()
{
double param, result;
param = 5.5;
result = log (param);
printf ("log(%f) = %f\n", param, result );
return 0;
}
log(5.500000) = 1.704748
#include <math.h>
double log10(double x);
x = 10ret
#include <math.h>
main(){
double answer;
answer = log10(100);
printf("log10(100) = %f\n", answer);
}
log10(100) = 2.000000
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