# -*- coding: UTF-8 -*-
for i in range(1,5):
 for j in range(1,5):
  for k in range(1,5):
   if (i != j) and (i != k) and (j != k):
    print i,j,k

# -*- coding: UTF-8 -*-
while True:
 I = input("pls input the lirun:")
 if I <= 10:
  a = I * 0.01
  print a
 elif I <= 20 and I > 10:
  b =0.25 + I * 0.075
  print b
 elif I <= 40 and I > 20:
  c = 0.75 + I * 0.05
  print c
 elif I <= 60 and I > 40:
  d = 0.95 + I * 0.03
  print d
 elif I <= 60 and I > 100:
  e = 2 + I * 0.015
  print e
 else:
  f = 2.95 + I * 0.01
  print f

# -*- coding: UTF-8 -*-
I = int(raw_input('净利润:'))
#这应该就是各个分界值了，把它们放在列表里方便访问
arr = [1000000,600000,400000,200000,100000,0] 
#这是各个分界值所对应的奖金比例值
rat = [0.01,0.015,0.03,0.05,0.075,0.1] 
 #这是总奖金的初始值
r = 0  
 #有6个分界值当然要循环6次     
for idx in range(0,6):  
 if I > arr[idx]:
  r = r + (I - arr[idx]) * rat[idx] 
  print (I - arr[idx]) * rat[idx]
  I = arr[idx]
print r

# -*- coding: UTF-8 -*-
import math
for i in range(10000):
 x = int(math.sqrt(i + 100))
 y = int(math.sqrt(i + 268))
 if (x * x == i + 100) and (y * y == i + 268):
  print i

# -*- coding: UTF-8 -*-
x = raw_input("请输入日期，比如20160506:")
year = int(x[:4])
month = int(x[4:6])
day = int(x[6:8])
month_day = [31,28,31,30,31,30,31,31,30,31,30,31]
data = sum(month_day[:(month-1)],day)
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
 if month > 2:
  data = data + 1
print "it is the %dth day"% (data)

# -*- coding: UTF-8 -*-
l = []
for i in range(3):
 x = int(raw_input('integer:\n'))
 l.append(x) #这里用append()函数，意思是追加元素
 l.sort()
print l

# -*- coding: UTF-8 -*-

x = input("input a num:")
y = input("input a num:")
z = input("input a num:")
temp = 0
if x < y:
 temp = x
 x = y
 y = temp
if x < z:
 temp = x
 x = z
 z = temp
if y < z:
 temp = y
 y = z
 z = temp
print z,y,x #由于上面是由小到大来比较和交换的，所以这里需要逆序输出

# -*- coding: UTF-8 -*-
x = input("input a num:")
y = input("input a num:")
z = input("input a num:")
y = [x,y,z] #注意，这里只能是列表，不能是元组，因为元组是不可改变的，你懂得！！
y.sort()
print y

# -*- coding: UTF-8 -*-
l1 = [1,2,3]
l2 = [4,5,6]
l1.append(l2)
print l1

输出：[1, 2, 3, [4, 5, 6]]

# -*- coding: UTF-8 -*-
l1 = [1,2,3]
l2 = [4,5,6]
print l1 + l2

输出：[1, 2, 3, 4, 5, 6]

# -*- coding: UTF-8 -*-
a = [1, 2, 3] #把列表a复制到列表b
b = a[:]
print b

# -*- coding: UTF-8 -*-
for i in range(1,10):
 for j in range(1,10):
  x = i * j
  print "%d * %d = %d" % (i,j,x)

# -*- coding: UTF-8 -*-
import time
d = {"a":1,"b":2}
for i in d:
 print i
 time.sleep(1) #暂停一秒输出

n = 1 时 f(1) = 1
n = 2 时 f(2) = 1
n = 3 时 f(3) = f(3-1) + f(3-2)
    = f(2) + f(1)
    = 1 + 1
    = 2
n = 4 时 f(4) = f(4-1) + f(4-2)
    = f(3) + f(2)
    = 2 + 1
    = 3
n = 5 时 f(5) = f(5-1) + f(5-2)
    = f(4) + f(3)
    = 3 + 2
    = 5
.....   ...

所以，当 n >= 2 时，表达式为f(n) = f(n-1) + f(n-2)

# -*- coding: UTF-8 -*-

def fib(n):
 a,b = 1,1
 for i in range(n-1):
  a,b = b,a+b
 return a

# 输出了第10个斐波那契数列
 print fib(10)

# -*- coding: UTF-8 -*-

# 使用递归
def fib(n):
 if n==1 or n==2:
  return 1
 return fib(n-1)+fib(n-2)

# 输出了第10个斐波那契数列
print fib(10)

# -*- coding: UTF-8 -*-

def fib(n):
 if n == 1:
  return [1]
 if n == 2:
  return [1, 1]
 fibs = [1, 1]
 for i in range(2, n):
  fibs.append(fibs[-1] + fibs[-2])
 return fibs

# 输出前 10 个斐波那契数列
print fib(10)

# -*- coding: UTF-8 -*-

f1 = 1
f2 = 1
for i in range(1,21):
 print 'ld ld' % (f1,f2),
 if (i % 3) == 0:
  print ''
 f1 = f1 + f2
 f2 = f1 + f2