其实bat中获取时间就是利用截取日期字符串的方法 DOS下有字符处理的方法的，总结如下： 在这个日期格式下：”2013-07-22 星期一”， 这个%DATE:~0,10%得到的是2013-07-22 说明：DATE为系统变量，“:”表示开始处理前面的字符串“~0,10”表示从第0个字符开始取10个字符。 输出： C:\Documents and Settings\Administrator>rem DOS get current time C:\Documents and Settings\Administrator>rem ======================= C:\Documents and Settings\Administrator>rem get yyyy/mm/dd C:\Documents and Settings\Administrator>set mydate=2013-07-22 C:\Documents and Settings\Administrator>echo 2013-07-22 2013-07-22 C:\Documents and Settings\Administrator>rem ======================= C:\Documents and Settings\Administrator>rem get yyyy C:\Documents and Settings\Administrator>set yyyy=2013 C:\Documents and Settings\Administrator>echo 2013 2013 C:\Documents and Settings\Administrator>rem ======================= C:\Documents and Settings\Administrator>rem get mm C:\Documents and Settings\Administrator>set mm=07 C:\Documents and Settings\Administrator>echo 07 07 C:\Documents and Settings\Administrator>rem ======================= C:\Documents and Settings\Administrator>rem get dd C:\Documents and Settings\Administrator>set dd=22 C:\Documents and Settings\Administrator>echo 22 22 C:\Documents and Settings\Administrator>rem ======================= C:\Documents and Settings\Administrator>rem get yyyy-mm-dd C:\Documents and Settings\Administrator>set curdate=2013  -07  -22 C:\Documents and Settings\Administrator>echo 2013  -07  -22 2013  -07  -22 C:\Documents and Settings\Administrator>