Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given s = "the sky is blue", return "blue is sky the". Could you do it in-place without allocating extra space?
func _reverseStr( _ chars:inout [Character], _ startIndex:Int, _ endIndex:Int){
var startIndex = startIndex
var endIndex = endIndex
if startIndex <= endIndex {
let tempChar = chars[endIndex]
chars[endIndex] = chars[startIndex]
chars[startIndex] = tempChar
startIndex += 1
endIndex -= 1
_reverseStr(&chars,startIndex,endIndex)
}
}
func reverseWords(_ str:String) -> String{
var chars = [Character](str.characters)
//首先翻转整个字符串所有字符,"the sky is blue" -> "eulb si yks eht"
_reverseStr(&chars,0,chars.count-1)
//然后翻转每个单词中的字符,"eulb si yks eht" -> "blue is sky the"
var startIndex = 0
for endIndex in 0 ..< chars.count {
if endIndex == chars.count - 1 || chars[endIndex + 1] == " " {
_reverseStr(&chars, startIndex, endIndex)
startIndex = endIndex + 2
}
}
return String(chars)
}
//翻转指定范围的字符
func _reverseStr( _ chars:inout [Character], _ startIndex:Int, _ endIndex:Int){
var startIndex = startIndex
var endIndex = endIndex
if startIndex <= endIndex {
let tempChar = chars[endIndex]
chars[endIndex] = chars[startIndex]
chars[startIndex] = tempChar
startIndex += 1
endIndex -= 1
_reverseStr(&chars,startIndex,endIndex)
}
}
//逐字翻转字符串
func reverseWords(_ str:String) -> String{
var chars = [Character](str.characters)
//首先翻转整个字符串所有字符,"the sky is blue" -> "eulb si yks eht"
_reverseStr(&chars,0,chars.count-1)
//然后翻转每个单词中的字符,"eulb si yks eht" -> "blue is sky the"
var startIndex = 0
for endIndex in 0 ..< chars.count {
if endIndex == chars.count - 1 || chars[endIndex + 1] == " " {
_reverseStr(&chars, startIndex, endIndex)
startIndex = endIndex + 2
}
}
return String(chars)
}
reverseWords("the sky is blue") //return "blue is sky the"
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